with statement 1 alone;
|x-3|>= y
we also know from the question that y>=0 so,
|x-3| >= y >= 0
because x-3 is in the absolute value notation x can be any number and the equation still works, so 1 is insufficient.
with statement 2 alone:
|x-3| <= -y
The only way that an absolute value can be less than or equal to a negative variable is if that variable is less than or equal to 0, so y<=0
but from the question y>=0.
The only way that this is true is if y=0 so, y=0
restating statement 2, |x-3| <= 0
The only way that an absolute value is less than or equal to zero is if that absolute value IS equal to zero...so x-3 = 0, thus x=3
B...Statement 2 alone is sufficient