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Expert replies
Source: — Problem Solving |

by GMATGuruNY » Sat Sep 29, 2012 12:30 pm
If n is a multiple of 5 and n = p^2q, where p and q are prime numbers, which of the following must be a multiple of 25?
a. p^2
b. q^2
c. pq
d. P^2q^2
e. p^3q
When a question asks for WHAT MUST BE X, try to prove that four of the answer choices DO NOT HAVE TO BE X.
The correct answer will be the remaining answer choice.

In order for n to be a multiple of 5, either p and/or q must be a multiple of 5.
Since the goal is to prove that four of the answer choices do NOT have to be a multiple of 25, start with the SMALLEST POSSIBLE COMBINATIONS.

Case 1: Let p=2 and q=5, so that n = 2²(5) = 20.

A) p² = 2² = 4. Not a multiple of 25. Eliminate A.
B) q² = 5² = 25. 25 is a multiple of 25. Hold onto B.
C) pq = 2*5 = 10. Not a multiple of 25. Eliminate C.
D) p²q² = 2²(5²) = 100. 25 is a multiple of 25. Hold onto D.
E) p³q = (2³)5 = 40. Not a multiple of 25. Eliminate E.

Case 2: Let p=5 and q=2, so that n = (5²)2 = 50.
B) q² = 2² = 4. Not a multiple of 25. Eliminate B.

The correct answer is D.
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by Anurag@Gurome » Sun Sep 30, 2012 6:39 pm
Mjkourtis wrote:If n is a multiple of 5 and n=P^2*Q, where P, Q prime, which is a multiple of 25?
a. P^2
B. Q^2
c. P*Q
d. P^2*Q^2
e. P^3*Q
If n is multiple of 5, and n = p²q where p and q are prime, then either p or q or both of them must be equal to 5. Let's analyze each of the cases. (Note that only one of the following can happen at a time)
1. p = 5, p² is multiple of 25, q² not
2. q = 5, q² is multiple of 25, p² not
3. p = q = 5, p² = q² = multiple of 25

We have to find a generalized expression containing p and q such that it becomes multiple of 25. From above analysis we know p² or q² is not that expression as they may or may not be a multiple of 25. But in p²q² both of them are present and simultaneously all the three cases are merged into one! For any of the above cases p²q² will be always a multiple of 25.

The correct answer is D.
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