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Target Test Prep · GMAT

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Chris Peckover
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Oct 13 to Jan 7, 2027

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Logan Thompson
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Sep 6 to Dec 6, 2026

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Sun · 9:30 AM to 12:30 PM ET
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Expert replies
Source: — Problem Solving |

by samirpandeyit62 » Sun Oct 07, 2007 7:23 am
If R=1+2xy+x^2y^2 , what is the value of xy??

(1)R=0
this is 1+2xy+x^2y^2 = (xy+1)^2

so (xy+1)^2 = 0

so xy =-1 SUFF

(2)x>0

(xy+1)^2 =R

here val cannot be determined coz R is not known

ans should be A
Regards
Samir
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