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by jjw.ashish » Thu May 22, 2008 3:11 am
Hi ,

For the question attached ,

The correct answer is option C II only.

I couldn't figure it how .

Suppose I take x = 16 , y = 9

sq root of x can be +4 , -4 . I choose -4
sq root of y can be +3 , -3 . I choose -3.

Now the equation becomes -7/25 which is less than 1/sq root of (x + y )
If I take sq root values as +ve then it becomes greater than 1/sq root of (x + y)

So I am getting two answers .

Is my logic flawed ? Please let me know .
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Source: — Data Sufficiency |
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by aatech » Thu May 22, 2008 5:45 am
I think you missed the part where it says x and y are +ve
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by amitansu » Fri May 23, 2008 12:51 am
Is it C i.e II only..
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by wawatan » Fri May 23, 2008 1:03 am
the answer is c.

try manipulating the equation . ...i will post explanation later
Last edited by wawatan on Fri May 23, 2008 1:41 am, edited 1 time in total.
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by amitansu » Fri May 23, 2008 1:10 am
I basically tried multiplying sqrt (x+y) to numerator for each of the given
data.
That makes q data is 1.

And then comparing whether 1 is greater than any of the given data..
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