Though I have arrived at the correct answer, I would like to know how to approach this problem. This is one of my weak areas in problem solving. Experts please help.
My approach:
One day job of six machines = 1/(12*6)
One day job of six + x machines = 1/[(6+x)*8] where x is the number of additional machines needed.
I equated the two equations above,
1/72=1/(48 + 8x)
48+8x = 72 => x=3.
Would be glad to know other approaches as well.
My approach:
One day job of six machines = 1/(12*6)
One day job of six + x machines = 1/[(6+x)*8] where x is the number of additional machines needed.
I equated the two equations above,
1/72=1/(48 + 8x)
48+8x = 72 => x=3.
Would be glad to know other approaches as well.
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Regards,
Pranay
Pranay
