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GMAT Prep - Tough PS Triangle, Coordinate Geometry

Problem Solving — algebra and arithmetic
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by albertrahul » Wed Jul 02, 2008 8:26 pm
Preety good question, though I got it wrong in first attempt.
A is not OA. I'll post OA after discussion.
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by simpdimp » Wed Jul 02, 2008 10:33 pm
Looks like a pretty simple question, let me know if I got it right!

(6+0+x)/3 = 3 and (0+0+y)/3 = 2 --> (3,6)
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by asigheartau » Fri Jul 04, 2008 9:24 am
simpdimp wrote:Looks like a pretty simple question, let me know if I got it right!

(6+0+x)/3 = 3 and (0+0+y)/3 = 2 --> (3,6)
If the values of x are the result of the average of the x vertices, shouldn't it be (6+0)/2=3 in which case y would be (0+2+Y)/3=??

Can you please detail your solution?
Alin Sigheartau
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by albertrahul » Sat Jul 05, 2008 6:50 am
Answer is (3,6).
This is actually a pretty simple question, but verbiage is confusing.

We've been told that values of x and y are average of respective vertices so value for x coordinate will be (6+0+x)/3 = 3.

Hope that helps!
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by tolmar » Sun Jul 13, 2008 12:00 pm
(3,6) to my opinion. This question is just long and cumbersome.
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