PLEASE EXPLAIN...
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But Moneyman, u r losing a point that is mentioned in the Qs - i.e. no of cow + no of pig = 40. Now if u plug stmt-1, it will work. Got my point? Let me know if I am wrong!moneyman wrote:The answer should be C
From the question we know that 40 are either Cows or Pigs
(1) Says that there are "More" than twice as many cows as pigs. Lets plug values and find out
if P=2 then C=38(more than twice as many pigs)
if p=6 then C=34(more than twice as many pigs)
So A is insufficient
(2) says that P>12. This information is insufficient as well.
When we combine both statements we know that P>12 and so
if p=13 then C=27(which is more than twice of P)
There is no ther combination which will satisfy the combined condition.
Hence the answer is C