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ikant
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Ok the soulution is like this.
stmt 1 :: if x is odd then x^2 is also odd and this makes x^2 + 1 even which in turn makes the product even,
stmt 2:: all prime factors greater then 7. this means that x^2 is an odd no since it has only odd prime nos, which again allows you to get the answer,
stmt 1 :: if x is odd then x^2 is also odd and this makes x^2 + 1 even which in turn makes the product even,
stmt 2:: all prime factors greater then 7. this means that x^2 is an odd no since it has only odd prime nos, which again allows you to get the answer,
"To do is to be"
