x {x is integer}, 2<k<8. Find k-?
st(1) k could be 1,2,3,5,6,10,15,30 OR (2^1)*(3^1)*(5^1)--> (1+1)(1+1)(1+1)=8 factors. Given 2<k<8 we deduce k must be only {3,5,6} Not Sufficient as three values satisfy k;
st(2) k could be 1,2,3,4,6,12 OR (2^2)*(3^1)--> (2+1)(1+1)=6 factors. Given 2<k<8 we deduce k must be only {3,4,6} Not Sufficient as three values satisfy k;
Combined st(1&2): k is factor of 30 and 12 means k could be {2,3,6} and with the condition given 2<k<8 we deduce k must be only {3,6} Still Not Sufficient, as two values satisfy k;
IOM
E
However, in the problem above I made assumption of x being k, as no other information about x was given - let k be integer.
luiscarlos59 wrote:Didnt find it on the search.
If x is an integer and 2<k<8, what is the value of k?
1)k is a factor of 30
2)k is a factor of 12
OA E
Although prime factorization brings 2*2*3 for 12, number 12 has
6 factors (sorry). Therefore, three possible factors satisfy to both conditions a) factor of 12 and b) 2<k<8; the factor numbers are 3, 4, and 6
luiscarlos59 wrote:
My question is in stmnt 2 12 can be factorized in 2*2*3 so that means that 3 is the only value between 2 and 8 so that would be suff?
