BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

GMAT Prep

Expert replies
Source: — Problem Solving |

by shovan85 » Sat Oct 02, 2010 12:56 am
All of them are true.

When you see this kind of problem make sure what is asked could or must be true.
if it is Must then try to prove one case where the concerned sentence will be wrong.
if it is Could then try to prove one case where the concerned sentence will be correct.

There is no simpler method than putting random values with an intelligent guess

1. x>y>z: any positive integers can be taken to prove so.
Say x = 16 y=2 and z =1

2. z>y>x: clue here is you have to take fractions here. say x=1/4 y=1/3 z = 1/2

3. x>z>y: as x will be greater than others z and y. so take x =1 y=1/3 z = 1/2

When see a could be kind of question try to manipulate the options with values like 0,1 and fractions
Join the discussion

by tlt2372 » Sat Oct 02, 2010 6:40 pm
For problems like this, I usually test cases.
Join the discussion

by ezhilkumarank » Sat Oct 02, 2010 8:20 pm
taneja.niks wrote:If x>y^2>z^4 which of the following could be true??

1) x>y>z
2) Z>y>x
3) X>z>y


Please explain how to approach such questions
Could be true -- any one set of data would suffice.

Plugging in different values for x, y and z would be sufficient to solve this problem.

Answer would be all of the above.
"The will-to-do achieves the deed, when the mind that wills is strong indeed"
Join the discussion