BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

GMAT Prep

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Newbie | Next Rank: 10 Posts
Posts: 4
Joined: Mon Jun 18, 2007 10:51 pm
by sahaldar » Mon Jul 16, 2007 2:34 am
Q) In a certain deck of card has a positive integers written on it. In a multiplication game, a child draw a card and multiplies the integer on the card by the next large integer. If each possible product is between 15 and 200, then the least and greates integers on the card could be.

a) 3 and 15
b) 3 and 20
c) 4 and 13
d) 4 and 14
e) 5 and 14

ans) C
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Junior | Next Rank: 30 Posts
Posts: 28
Joined: Wed Jun 13, 2007 3:10 pm
Location: NJ, USA

by blah45 » Mon Jul 16, 2007 5:27 am
15 < product < 200
Let's start with the upper limit of 200. How do we get the product? By multiplying two consecutive numbers (i.e., the number that was picked and the next larger number which would be the very next number after the one that was picked).

So, n_max * (n_max + 1) < 200
we know 13 * 13 = 169 (if you don't remeber this then you can always start @ 10 *11 = 110 and work your way up). 13* 13 is not valid b/c both numbers have to be different. So, we can try 13* 14 and then 14* 15.

13 * 14 = 182
14 * 15 = 210.

so, n_max = 13. At this point we already know that the answer is (C).

Just to complete the problem ...
Similarly, n_min * (n_min + 1) > 15. We know that 4 * 4 = 16 (again, this is not valid b/c both numbers have to be different). so, 4 * 5 = 20. That meets the requirement.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1