Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

GMAT Prep

Expert replies
by sahaldar » Mon Jul 16, 2007 2:34 am
Q) In a certain deck of card has a positive integers written on it. In a multiplication game, a child draw a card and multiplies the integer on the card by the next large integer. If each possible product is between 15 and 200, then the least and greates integers on the card could be.

a) 3 and 15
b) 3 and 20
c) 4 and 13
d) 4 and 14
e) 5 and 14

ans) C
Join the discussion
Source: — Problem Solving |

by blah45 » Mon Jul 16, 2007 5:27 am
15 < product < 200
Let's start with the upper limit of 200. How do we get the product? By multiplying two consecutive numbers (i.e., the number that was picked and the next larger number which would be the very next number after the one that was picked).

So, n_max * (n_max + 1) < 200
we know 13 * 13 = 169 (if you don't remeber this then you can always start @ 10 *11 = 110 and work your way up). 13* 13 is not valid b/c both numbers have to be different. So, we can try 13* 14 and then 14* 15.

13 * 14 = 182
14 * 15 = 210.

so, n_max = 13. At this point we already know that the answer is (C).

Just to complete the problem ...
Similarly, n_min * (n_min + 1) > 15. We know that 4 * 4 = 16 (again, this is not valid b/c both numbers have to be different). so, 4 * 5 = 20. That meets the requirement.
Join the discussion