Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

GMAT Prep-Statistics Problem.

Expert replies
by lokesh r » Sun Oct 10, 2010 12:40 pm
A set of 15 different integers has a median of 25 and range of 25, what is the greatest possible integer that could be in the set.
1) 32
2) 37
3) 40
4) 43
5) 50

Ans. d

I solved the question as below

let set be x, x1...25....y

given y-x=25
y=x+25.

Now to make y maxmimum, we have take maximum possible value of x that could be 25
so y=25+25=50, where am i going wrong? pls help
Join the discussion
Source: — Problem Solving |

by Ian Stewart » Sun Oct 10, 2010 12:52 pm
Your answer would be right except that the question tells us that the integers in the set are all *different*. If the question didn't say that, your answer is correct. Here, if 25 is the median, there are seven elements smaller than 25, and the largest values the eight smallest things in the set can have are:

18, 19, 20, 21, 22, 23, 24, 25

So if the range is 25, the largest value possible for the largest element is 18+25 = 43.
For online GMAT math tutoring, or to buy my higher-level Quant books and problem sets, contact me at ianstewartgmat at gmail.com

ianstewartgmat.com
Join the discussion

by lokesh r » Sun Oct 10, 2010 1:09 pm
Ian Stewart wrote:Your answer would be right except that the question tells us that the integers in the set are all *different*. If the question didn't say that, your answer is correct. Here, if 25 is the median, there are seven elements smaller than 25, and the largest values the eight smallest things in the set can have are:

18, 19, 20, 21, 22, 23, 24, 25

So if the range is 25, the largest value possible for the largest element is 18+25 = 43.
I think i am hurrying myself to solve problem..rather than reading question carefully...thanks very much..
Join the discussion