Let angle RSQ = y and angle UST = zatarafder wrote:How do I solve this? Thanks in advance.
We have x + y + z = 180
1 - insufficient. In triangle RQS, 2y + angle-QRS = 180
2 - insufficient. In triangle STU, 2z + angle-UTS = 180
Combining and adding both,
2y + angle-QRS + 2z + angle-UTS = 360
We know angle-QRS + angle-UTS = 90 degrees (if you take triangle
PRT, one angle is 90 degrees)
2y + 2z = 360 - 90
y + z = 135
We also have x + y + z = 180 (straight line).
So we can compute x.
Hence C
