Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

gmat prep -sequence question

Expert replies
by xcise_science » Tue Nov 20, 2007 5:59 pm
Can someone help with this?
I thought I was good with sequence questions but I had absolutely no idea what to do with this when I saw it.

Thanks!

Image
Join the discussion
Source: — Problem Solving |

by gmatrant » Tue Nov 20, 2007 6:36 pm
Its a AP series.

Term = a + (n-1)d
where a = first term
n = nth term
d = difference

So here a =23, d=-3 and we need to find the nth term whose value is -4.

23+ (n-1)*-3 = -4
-3n+3 = -27
n = 10

Is the OA 10
Join the discussion

by xcise_science » Tue Nov 20, 2007 7:37 pm
Thanks, but I don't understand what you meant here:

Term = a + (n-1)d
where a = first term
n = nth term
d = difference

So here a =23, d=-3 and we need to find the nth term whose value is -4.

How did you know the first term was 23?

Also, whats an AP? Arithmetic progression?

Thanks
Join the discussion

by ri2007 » Wed Nov 21, 2007 6:12 am
gmatrant

I got the same sanswer as u, used the same AP formula :)) but when I saw the ans given by the GMAT prep people it is 14.

Any thoughts?
Join the discussion

by jrbrown2 » Wed Nov 21, 2007 8:45 am
I used the AP formula and did it manually
tn=t1 + (n-1)d
-4=23+(n-1)(-3)
n=10

23, 20, 17, 14, 11, 8, 5, 2, -1, -4 <----10th term

can't see how 14 is the answer (t1 would have to be 35 for n to be 14).
Join the discussion

by xcise_science » Wed Nov 21, 2007 9:00 am
But I'm still somewhat unclear as to this AP thing, especially this: tn=t1 + (n-1)d
where do I get more information on how to attack this?

thanks!
Join the discussion

by jrbrown2 » Wed Nov 21, 2007 9:14 am
It's an arithmetic sequence. the question states that each consecutive term is 3 less than the previous.

for instance, the 3rd term would be 3 less than the second term, which is 3 less than the first term (hope thats clear)

1st term = 23
2nd term = 23-3 or 23+(1)(-3) = 20
3rd term = 23-3-3 or 23+(2)(-3) = 17
4th term = 23-3-3-3 or 23+(3)(-3) = 14
and so on...

To rewrite this into a formula, the value of the nth term would be 23+(n-1)(-3)
i.e. Value of nth term = 1st term + (n -1)(difference)
or
Tn = T1 + (n-1)d
Last edited by jrbrown2 on Wed Nov 21, 2007 10:34 am, edited 4 times in total.
Join the discussion

by ri2007 » Wed Nov 21, 2007 9:14 am
Join the discussion

by xcise_science » Wed Nov 21, 2007 10:14 am
OOPS! forgive me! I didn't see that little comma that said T(1)=23!
For some reason, I thought that was a continuation from T(n)...
Now it makes sense, cos I was wondering how you determined that T(1)=23..

Thanks for your help!
(so can this formula be used for any sortof progression question?)
Join the discussion

by jrbrown2 » Wed Nov 21, 2007 10:32 am
this formula can only be used for addition.
For different types of progressions, check that link that r12007 posted. It's pretty good.
Join the discussion

by Jimat » Thu Nov 22, 2007 9:41 am
I still don`t get it. The questions says what is the value of N when Tm =-4, what jrbrown has answered is what is the value of the 4th term.
Join the discussion