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by moneyman » Fri Nov 09, 2007 10:22 pm
A certain roller coaster has three cars, and a passenger is equally likely to ride in any 1 of the 3 cars each time that passenger rides the roller coaster. If a certain passenger is to ride the roller coaster 3 times, what is the probabilitiy that the passenger will ride each of the 3 cars??

0
1/9
2/9
1/3
1
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by samirpandeyit62 » Sat Nov 10, 2007 7:20 am
3!/3^3

=6/27 =2/9 C
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by moneyman » Sat Nov 10, 2007 8:44 pm
Hey Samir dont mind but can you please explain how you arrived at the answer because I am not that good at probability questions.. :oops:
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by samirpandeyit62 » Sat Nov 10, 2007 10:50 pm
let the cars be represented by A,B,C

so total possibilities = 3*3*3 (each time he can select one of the 3 cars)

& for him to select each of the cars A,B,C, he can do this using all permutations of ABC i.e 3!

so reqd P =3!/3^3 =2/9

Sorry Moneyman for not providing the expln, actually I'm trying to practise solving Q's on the scratch paper. 8)
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