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by dferm » Thu Nov 29, 2007 9:24 am
CAN SOMEONE PLEASE HELP WITH THIS QUES?

At a certain college there are twice as many English majors as history majors adn three times as many English majors as mathematics majors. What is the ratio of the number of history majors to the number fo mathmatics majors?

A. 6 to 1
B. 3 to 2
C. 2 to 3
D. 1 to 5
E. 1 to 6

Please elaborate how you arrive at your answer..thanks.
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by sankruth » Thu Nov 29, 2007 9:30 am
E:H = 2:1
E:M = 3:1

Using common multiples, we can say:
E:H = 6:3
E:M = 6:2

so, E:H:M = 6:3:2
and H:M = 3:2

(B) Is it correct?
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by blanca » Thu Nov 29, 2007 10:29 am
H=E/2 and
M=E/3

Ration of H to M is H/M = E/2 divided by E/3
i.e E/2 * 3/E = 3/2

So H:M is 3:2 .
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by Patrick_GMATFix » Wed Jul 21, 2010 6:34 am
Easiest way to solve this is to plug in. English is twice history and English is three times math. So start by plugging a reasonable value for English.

English=6 >> History=3 >> Math=2

Ratio of History to Math is 3:2. Pick B.

2 ways to solve as well as a step-by-step video solution are available at GMATPrep Question 1313. To create drills with similar questions, set topic='FDPs & Ratios' and difficulty='400-500'

-Patrick
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