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GMAT Prep - Rate, Distance

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Senior | Next Rank: 100 Posts
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by albertrahul » Mon Jul 14, 2008 8:13 pm
I initially chose A and I understand why it is incorrect. However, I don't understand why answer cannot be C?


Please help.
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Source: — Data Sufficiency |
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by iamabhisheksingh » Mon Jul 14, 2008 9:03 pm
From 1) you find out that the distance is greater than 5.4 something
From 2) you know the distance is less than 6.1 something..

This just gives the range. The speed could be anything b/w 16f/s to 18f/s could be 7.99 or 16.01. So neither statement tells u the whether the distance was greater than 6.
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by beeparoo » Wed Jul 16, 2008 5:31 pm
Is it just me or does anyone find that this question requires a lot of long-division and ugly pen-on-paper calculation to solve?

Finding that the question is just "E" makes me feel all, "meh". It's like the payoff isn't worth it.
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by albertrahul » Wed Jul 16, 2008 6:28 pm
I second you my friend.
This question does require lengthy calculation and then u find that answer is E. :(
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by Mclaughlin » Thu Jul 17, 2008 8:48 am
iamabhisheksingh wrote:From 1) you find out that the distance is greater than 5.4 something
From 2) you know the distance is less than 6.1 something..

This just gives the range. The speed could be anything b/w 16f/s to 18f/s could be 7.99 or 16.01. So neither statement tells u the whether the distance was greater than 6.
How did you calculate those distances?
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by moliver » Thu Jul 17, 2008 12:37 pm
Mclaughlin wrote:
iamabhisheksingh wrote:From 1) you find out that the distance is greater than 5.4 something
From 2) you know the distance is less than 6.1 something..

This just gives the range. The speed could be anything b/w 16f/s to 18f/s could be 7.99 or 16.01. So neither statement tells u the whether the distance was greater than 6.
How did you calculate those distances?
1) D = V*T
V= 16 ft/s = 16*60*60 ft/hours = 16*3600/5280 miles/hours
D= V*T = V/2 = 5.45

2) The same, but this time V = 18 ft/s
then D= 6.1

and 5.45 < D < 6.1

We don't know if D is greater than 6 miles, so it must be a E.


beeparoo I agree with you.
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