Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

GMAT Prep Question:

Expert replies
by mpaudena » Tue Feb 17, 2009 8:00 pm
Okay, here is a question from the GMAT software test. I couldn't copy and paste the image so please bare with me as I describe the image; it's pretty simple:

Two triangles - one appears larger than the other, but the question says that the figures are not drawn to scale. The angles of triangle 1 and triangle 2 are labelled x, y, and z indicating that the triangles have congruent angles. On the small triangle there is a side that is labelled "s" and on the large triangle the corresponding side is labelled "S."

Now the question:

In the figures above, if the area of the larger triangle is twice the area of of the smaller triangle, then in terms of s, S =

A) (square root of 2/2)s

B) (square root of 3/2)s

C) (square root of 2)s

D) (square root of 3)s

E) (2)s
Join the discussion
Source: — Problem Solving |

by tini » Tue Feb 17, 2009 8:10 pm
I just solved it yesterday. Its very simple. You should know the property of similar triangles. If two triangles are similar then their areas are in proportion to the square of the sides.

the triangles are similar as per AAA property:

so area of the triangle with side S/area of the triangle with side s = (S/s)^2

So, (S/s)^2=2 (as per the question area of the triangle with side S is twice the area of the other)

so , S= sqrt2s
Join the discussion

by mpaudena » Wed Feb 18, 2009 7:41 am
tini wrote:I just solved it yesterday. Its very simple. You should know the property of similar triangles. If two triangles are similar then their areas are in proportion to the square of the sides.

the triangles are similar as per AAA property:

so area of the triangle with side S/area of the triangle with side s = (S/s)^2

So, (S/s)^2=2 (as per the question area of the triangle with side S is twice the area of the other)

so , S= sqrt2s
Thanks for the response but you lost me. What does AAA property mean? Also, I don't understand why (S/s) is squared. The question says S = 2s so shouldn't it be S/s = 2? Thanks.
Join the discussion

by tini » Wed Feb 18, 2009 7:46 am
Join the discussion

by tini » Wed Feb 18, 2009 7:48 am
also refer to :
https://www.onlinemathlearning.com/simil ... es.html#aa

AA is a rule to prove that two triangles are similar
Join the discussion