GMAT Prep question

willymtz wrote:According to the directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice. How many 12-ounce cans of the concentrate are required to prepare 200 6-ounce servings of orance juice.

a. 25
b. 34
c. 50
d. 67
e. 100

How to solve?

200 6-ounce servings of OJ contains 1/4*200 = 50 6-ounce servings
of concentrate.

50 6-ounce servings = 25 12-ounce servings.

Hence A

1 ounce of C
3 ounce of water

total 4 ounce to make OJ

convert everything to ounces

200 cans of 6 ounces of OJ is 1200 ounces

how many groups of 1200 ounces of 4 ounce of OJ... is 300

since we have to multiply by 300, go back and times 300 to the original ratio... 1 C * 300= 300 ounces of concentrate

but since we want 12 ounce cans, we get 300/12= 25



ans =A

According to the directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice. How many 12-ounce cans of the concentrate are required to prepare 200 6-ounce servings of orance juice.

a. 25
b. 34
c. 50
d. 67
e. 100

1 can juice + 3 cans water = Orange juice
Ratio = 1:3

200-6 ounce servings will have 1 part concentrate and 3 parts water

1200 ounce will have 300 ounces of concentrate and 900 ounces of water
so number of 12-ounce cans = 300/12 = 100/4 = 25