Please explain why 2nd stmt. is not sufficient?
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Priyanka
Priyanka
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(2) the y intercept of k is -6priyankamishra11 wrote:Please explain why 2nd stmt. is not sufficient?

Hi Stuart,Stuart Kovinsky wrote:(2) the y intercept of k is -6priyankamishra11 wrote:Please explain why 2nd stmt. is not sufficient?
Well, if the equation of line k is y=-6, then k will not intersect sector II.
If the equation of line k is y = -(1/6)x - 6, then k will intersect sector II.
So, the answer could be "no" or "yes": insufficient.
Here's the general rule on which you're being tested:
A line with a negative slope will ALWAYS intersect sectors II and IV. (It will also pass through one of the other sectors, unless it passes through the origin.)
A line with a positive slope will ALWAYS intersect sectors I and III. (It will also pass through one of the other sectors, unless it passes through the origin.)
All we know from statement (2) is that the y intercept is -6.anju wrote:Hi Stuart,Stuart Kovinsky wrote:(2) the y intercept of k is -6priyankamishra11 wrote:Please explain why 2nd stmt. is not sufficient?
Well, if the equation of line k is y=-6, then k will not intersect sector II.
If the equation of line k is y = -(1/6)x - 6, then k will intersect sector II.
So, the answer could be "no" or "yes": insufficient.
Here's the general rule on which you're being tested:
A line with a negative slope will ALWAYS intersect sectors II and IV. (It will also pass through one of the other sectors, unless it passes through the origin.)
A line with a positive slope will ALWAYS intersect sectors I and III. (It will also pass through one of the other sectors, unless it passes through the origin.)
Can you pls. elaborate :
If the equation of line k is y = -(1/6)x - 6, then k will intersect sector II.
So, the answer could be "no" or "yes": insufficient.
How did u get this equaltion from statement 2 alone?
Thanks
