GMAt prep Question no 2

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subhasis8877: Senior | Next Rank: 100 Posts; Posts: 77; Joined: Tue Mar 10, 2009 3:10 am

by subhasis8877 » Tue Aug 18, 2009 8:05 am

Please refer the attachment

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Source: Beat The GMAT — Problem Solving | Tue Aug 18, 2009 8:05 am

prindaroy: Master | Next Rank: 500 Posts; Posts: 113; Joined: Thu Jul 16, 2009 11:23 am; Thanked: 15 times; GMAT Score:730

by prindaroy » Tue Aug 18, 2009 11:25 am

area of circular glass = pi*(r-s)^2

area of full thing = pi*(r^2)

area of shaded thingy: pi(2rs-s^2)

= pi*s*(2r-s)

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