BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

GMAT Prep Question - Inequality

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Senior | Next Rank: 100 Posts
Posts: 30
Joined: Thu Jan 17, 2008 5:38 pmFollowed by: 1 member
GMAT Score:680
by dongkim2 » Wed Jun 16, 2010 11:50 am
M + Z > 0?

(1) M - 3Z > 0

(2) 4Z - M > 0

OA: C

[spoiler]Since I couldn't answer for the above based on (1) and (2) individually, I combined (subtraction is not allowed) both inequalities and came up with Z > 0. Based on (1), I came up with M > 3Z > 0. Therefore, I concluded M + Z is greater than 0. Please let me know my reasoning was correct. Thanks![/spoiler]
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Data Sufficiency |
User avatar
Master | Next Rank: 500 Posts
Posts: 106
Joined: Mon Sep 28, 2009 9:29 amFollowed by: 2 members
Location: Boston, MA
Thanked: 26 times
GMAT Score:700

by asamaverick » Wed Jun 16, 2010 12:06 pm
Your reasoning is perfectly fine.

There is another way to do this.
Multiply (1) by 5 to get - > 5M - 15Z > 0
Multiply (2) by 4 to get - > 16Z - 4M > 0

Add the two and you get:
M + Z > 0
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 186
Joined: Fri May 28, 2010 1:05 am
Thanked: 11 times

by jube » Thu Jun 17, 2010 10:00 am
1) M > 3Z - insuff
2) 4Z > M - insuff.

1&2 combined: 4Z > M > 3Z. So, if:

both M &Z are +ve and M+Z>0
both M&Z are -ve and M+Z<0

Isn't this also insuff. since M+Z can be either positive or negative?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 2326
Joined: Mon Jul 28, 2008 3:54 amFollowed by: 2 members
Thanked: 173 times
GMAT Score:710

by gmatmachoman » Thu Jun 17, 2010 12:09 pm
jube wrote:1) M > 3Z - insuff
2) 4Z > M - insuff.

1&2 combined: 4Z > M > 3Z. So, if:

both M &Z are +ve and M+Z>0
both M&Z are -ve and M+Z<0

Isn't this also insuff. since M+Z can be either positive or negative?
I liked ur way of "out of box " reasoning..But but there is a glitch!

U said very clearly 4Z>M and 4Z> 3Z

So as per ur second statement both M&Z are -ve and M+Z<0

Z cannot be Negative !! :)

If Z is <0 then 4Z cannot be greater that 3Z..That would violate the deductions!!

So for 4Z to be greater than 3Z, Z has to be greater than zero!!

It becomes like 4z>3Z>0 !!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 186
Joined: Fri May 28, 2010 1:05 am
Thanked: 11 times

by jube » Fri Jun 18, 2010 6:43 am
gmatmachoman wrote:
jube wrote:1) M > 3Z - insuff
2) 4Z > M - insuff.

1&2 combined: 4Z > M > 3Z. So, if:

both M &Z are +ve and M+Z>0
both M&Z are -ve and M+Z<0

Isn't this also insuff. since M+Z can be either positive or negative?
I liked ur way of "out of box " reasoning..But but there is a glitch!

U said very clearly 4Z>M and 4Z> 3Z

So as per ur second statement both M&Z are -ve and M+Z<0

Z cannot be Negative !! :)

If Z is <0 then 4Z cannot be greater that 3Z..That would violate the deductions!!

So for 4Z to be greater than 3Z, Z has to be greater than zero!!

It becomes like 4z>3Z>0 !!
Ahh!! I see the mistake I was making! Thank you!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1