BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

GMAT Prep Question Exponents

Expert replies
Source: — Problem Solving |

by sankruth » Sun Jan 27, 2008 1:04 am
Simplifying the exponents you get...

2^[(x+y)^2 - (x-y)^2]

The exponent part can be ssimplified as follows:

[(x+y)+(x-y)].[(x+y)-(x-y)]

2x.2y = 4xy = 4 (B)
Join the discussion

by cris » Sun Jan 27, 2008 7:09 am
I think is D.

What is the correcty answer??
Join the discussion

by Yuke » Sun Jan 27, 2008 10:40 am
Yes its D. I was making a mulitplication error and things were not canceling out. I figured it out in my sleep last nite. :D

Thanks for the help.
Join the discussion

by sibbineni » Sun Jan 27, 2008 1:21 pm
2^(x+y)2/2^(x-y)2

=2^(x^2+y^2+2xy)/2^(x^2+y^2-2xy)


since a^x/a^-y=a^(x+y)

then 2^(x^2+y^2+2xy-x^2-y^2+2xy)

=2^(4xy)

since xy=1

=2^4
=16

Suggest me if iam wrong
Join the discussion

Re: GMAT Prep Question Exponents

by Stuart@KaplanGMAT » Sun Jan 27, 2008 3:55 pm
Yuke wrote:Here is the questions. Thanks for the help.

If xy=1, what is the value of

2^(x+y)^2 divided by 2^(x-y)^2

a) 2
b) 4
c) 8
d) 16
e) 32
Alternately, we can just pick numbers... which will make our lives MUCH simpler.

We know that xy=1, so let's pick x=1 and y=1.

Now we have 2^2^2/2^0^2 = 2^4/2^0 = 16/1 = 16: choose (D)
Image

Stuart Kovinsky | Kaplan GMAT Faculty | Toronto

Kaplan Exclusive: The Official Test Day Experience | Ready to Take a Free Practice Test? | Kaplan/Beat the GMAT Member Discount
BTG100 for $100 off a full course
Join the discussion

by yalephd2007 » Wed Apr 16, 2008 4:37 pm
I choose D
Join the discussion

Re: GMAT Prep Question Exponents

by aj5105 » Thu May 07, 2009 11:13 am
Yup, using numbers - the problem gets simpler.
Stuart Kovinsky wrote:
Yuke wrote:Here is the questions. Thanks for the help.

If xy=1, what is the value of

2^(x+y)^2 divided by 2^(x-y)^2

a) 2
b) 4
c) 8
d) 16
e) 32
Alternately, we can just pick numbers... which will make our lives MUCH simpler.

We know that xy=1, so let's pick x=1 and y=1.

Now we have 2^2^2/2^0^2 = 2^4/2^0 = 16/1 = 16: choose (D)
Join the discussion

by barnesthad » Wed Jul 22, 2009 4:55 am
If you pick numbers and x=0.5 and y=2 then the answer is 8 (C). If you pick x=1 and y=1 then the answer is 16 (D). Unless it is stated that x and y are integers it's not a "given." Guessing in this situation is risky. I would work the problem.
Join the discussion

by Stuart@KaplanGMAT » Wed Jul 22, 2009 7:36 am
barnesthad wrote:If you pick numbers and x=0.5 and y=2 then the answer is 8 (C). If you pick x=1 and y=1 then the answer is 16 (D). Unless it is stated that x and y are integers it's not a "given." Guessing in this situation is risky. I would work the problem.
There is absolutely 0 risk in picking numbers on this question.

Here's a fundamental rule of the GMAT:

Every question on the test has 1 right answer and 4 wrong answers. There has never been a GMAT question with more than 1 correct answer.

Here's a corollary to that rule:

If you ever find two right answers to a question, you have made a mistake.

And one more corollary for free questions that you find on the internet:

If a question does have two correct answers, then it is not a real GMAT question.

How do we know that picking numbers is safe on this particular question? Because all of the answer choices are numbers. Since it's impossible (by GMAT rules) to have more than one correct answer, as soon as we find a match, we know we've got the right choice.

I agree that, on this particular question, different numbers lead to different answers. I didn't even check any other numbers because the question is labeled as "GMAT Prep", a usually reliable source (since GMAT Prep should refer to questions from the official CATs composed of retired GMAT questions).

So, what should we take away from this experience?

1) if the answer choices are all numbers, it's 100% safe to pick numbers on that question (if one of the choices had been "it cannot be determined from the information given", then we'd have to try multiple numbers to be sure of our first result);

2) if you're posting a question on this board, please make sure to accurately cite the source and to properly reproduce the question; and

3) don't trust every question you find on the internet!
Image

Stuart Kovinsky | Kaplan GMAT Faculty | Toronto

Kaplan Exclusive: The Official Test Day Experience | Ready to Take a Free Practice Test? | Kaplan/Beat the GMAT Member Discount
BTG100 for $100 off a full course
Join the discussion

by Ian Stewart » Wed Jul 22, 2009 8:50 am
barnesthad wrote:If you pick numbers and x=0.5 and y=2 then the answer is 8 (C). If you pick x=1 and y=1 then the answer is 16 (D). Unless it is stated that x and y are integers it's not a "given." Guessing in this situation is risky. I would work the problem.
There's only one answer to the problem. If you pick the numbers 0.5 and 2, you will also get 16:

2^(2 + 0.5)^2 / 2^(2 - 0.5)^2
= 2^(2.5)^2 /2^(1.5)^2
= 2^(2.5^2 - 1.5^2)
= 2^[(2.5 + 1.5)(2.5 - 1.5)]
= 2^(4*1)
= 16
For online GMAT math tutoring, or to buy my higher-level Quant books and problem sets, contact me at ianstewartgmat at gmail.com

ianstewartgmat.com
Join the discussion