BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

GMAT PREP QUES

Expert replies
by dhanda.arun » Sat Nov 01, 2008 11:16 am
If the operation X is one of the four arithmetic operations addition, subtraction, multiplication and divison, is (6X2)X4 = 6X(2X4)
1. 3X2 > 3
2. 3X1 = 3

OA IS CONDITION I IS SUFFICIENT

BUT AS PER MY UNDERSTANDING , CONDITION2 IS SUFFICIENT

KINDLY EXPLAIN
Join the discussion
Source: — Problem Solving |

by stop@800 » Sat Nov 01, 2008 11:34 am
I somehow missed my detailed explanation.
Rewriting in brief, let me know if it odes not suffice

Qn want operator to be * or +

A
true only for * and +, hence suff

B
true for * and / so not suff


The property asked is known as associative property of operators.
Join the discussion

by stop@800 » Sat Nov 01, 2008 11:35 am
Join the discussion