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GMAT Prep - Quant 2

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by Sumit69 » Sun Apr 05, 2009 1:46 am
Dear Ian\Stuart,

Please suggest the best and the quickest way to solve these type of questions.

Rgds,
Sumit
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by chetanojha » Mon May 04, 2009 3:35 am
Lets pick numbers, since both are positive. Let x=16 and y=9 (i pick perfect squares to its easy to compute values)

you need the answer which is greater than 1/sqrt(x+y). i.e 1/sqrt(16+9)=1/5=>0.2

Now plug the above value of x and y and you will find:

1.sqrt(x+y)/2x=sqrt(16+9)/2*16=>5/32=>0.15 Not correct.

2.sqrt(16)+sqrt(y)/(x+y)=>sqrt(16)+sqrt(9)/(16+9)=>9/25=>0.36 Correct.

3.sqrt(16)-sqrt(y)/(x+y)=>sqrt(16)-sqrt(9)/(16+9) =>1/25 => 0.04 Not correct

Hence answer II only.
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by bmlaud » Mon May 04, 2009 9:56 am
If you don't want to choose numbers then the best method is to make denominators of the fractions same and compare the numerators.
The fractions reduce down to following comparisons

Option1: Is 2x(sqrt(x+y)) > (x+y)(sqrt(x+y)) => is 2x>(x+y)
True only when x>y - can't say

Option2: Is (sqrt(x) + sqrt(y)) > (sqrt(x+y))
squaring both sides ( x+y+2sqrt(x)sqrt(y)) > (x+y) => yes true

Option3: Is (sqrt(x) - sqrt(y)) > (sqrt(x+y)) ; again squaring both sides
we get ( x+y-2sqrt(x)sqrt(y)) > (x+y) => No
"Great works are performed not by strength but by perseverance."
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Re: GMAT Prep - Quant 2

by Vemuri » Tue May 05, 2009 11:09 pm
My 2 cents.....pick numbers appropriate. Its the fastest way to solve these kind of questions. You don't want to be bogged down by time in the real exam.
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