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by singh21 » Mon Mar 16, 2009 2:32 pm
Any suggestions to tackle this problem within 2-3 min? Thanks!!!
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Source: — Data Sufficiency |
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by cramya » Mon Mar 16, 2009 2:43 pm
To get the mimimum for 1 of the 11 districts maxmize the other 10


1.1x-> At the max any district could be atmost 10% more than the lowest populated district


132000 = x + 10* 1.1x

x = 11000
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Junior | Next Rank: 30 Posts
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by singh21 » Mon Mar 16, 2009 4:04 pm
Thanks Cramya !!! did not think along those lines ... :D
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by cramya » Mon Mar 16, 2009 4:08 pm
Trust me, its just a matter of time before u do. Keep up the hardwork and good luck....

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CR
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by hk » Tue Mar 17, 2009 10:43 am
cramya wrote:To get the mimimum for 1 of the 11 districts maxmize the other 10


1.1x-> At the max any district could be atmost 10% more than the lowest populated district


132000 = x + 10* 1.1x

x = 11000
Can you please elaborate on this one cramya?? I dont seem to understand how you came up with that equation.

Thanks
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by cramya » Tue Mar 17, 2009 1:29 pm
Can you please elaborate on this one cramya?? I dont seem to understand how you came up with that equation.

1.1 x is that each of the 10 other districts has the maximum allowed 10% more than the lowest district

The total 132000 = lowest ditrict count + 10 other district maximum counts
= x + 10 * 1.1x (since 1 district is 1.1x 10 districts is 10*1.1x)

Hope this helps.

Regards,
Cr
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