GMAT prep PS question
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The question asks for perimeter
P = 0.5[pi*r] + 2*r
r =100
P = 100[ pi/2 + 2]
pi =3.14. so pi/2 =1.57
P = 100[1.57+2] = 100[3.57] = 357
Hope this is a simpler method
P = 0.5[pi*r] + 2*r
r =100
P = 100[ pi/2 + 2]
pi =3.14. so pi/2 =1.57
P = 100[1.57+2] = 100[3.57] = 357
Hope this is a simpler method