1) If x<0, then squareroot(-x|x|) is
a) -x b) -1 c) 1 d) x e)squareroot(x)
OA is A)
My approach is
since x<0 take x as -2 then sub in above equation, we get
squareroot(-(-2)|2|)= squareroot(4)= +- 2, since x<0 we get -2
we took x as -2 and we got answer as -2.
So answer is x, but in prep answer is given as A) ....why so????
2) What is the greatest possible area of a triangluar region with one vertex at the center of the circle of radius 1 and the other two vertices on the circle?
a) squareroot(3) / 4 b) 1/2 c) pie/4 d)1 e)squareroot(2)
OA is 1 /2 i.e B
a) -x b) -1 c) 1 d) x e)squareroot(x)
OA is A)
My approach is
since x<0 take x as -2 then sub in above equation, we get
squareroot(-(-2)|2|)= squareroot(4)= +- 2, since x<0 we get -2
we took x as -2 and we got answer as -2.
So answer is x, but in prep answer is given as A) ....why so????
2) What is the greatest possible area of a triangluar region with one vertex at the center of the circle of radius 1 and the other two vertices on the circle?
a) squareroot(3) / 4 b) 1/2 c) pie/4 d)1 e)squareroot(2)
OA is 1 /2 i.e B
