IMO A
Op A
1/(k-1) > 0
=> k-1 has to be greater than 0 and k not equal to 1
so, k-1 > 0 => k > 1
if K is greater then 1 then 1/k will always be greater then 0, hence sufficient
Op B
1/(k+1) > 0
=> k+1 > 0 => k > -1
if k is b/w -1 < k < 0, then 1/k < 0
if k > 0 then 1/k > 0
As we are getting two possibilities, so insufficient
Hence A
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1/k > 0 ? Is k > 0?
STMT A = k > 0 but does not include 1
STMT B = k could be (-) from -1 to 0 exclusive or (+) from 0 to 1 exclusive
IMO A
STMT A = k > 0 but does not include 1
STMT B = k could be (-) from -1 to 0 exclusive or (+) from 0 to 1 exclusive
IMO A
naveenhv wrote:If k is not equal to 0,1 or -1, is 1/k > 0?
1) 1/(k-1) > 0
2) 1/(k+1) > 0
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