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GMAT Prep: Median

Expert replies
Source: — Problem Solving |

by StarDust845 » Thu Dec 27, 2007 3:06 pm
0<x<1

For given x, sqrt(x) is greater than x.
square(x) is less than x.
cube(x) will be less than square(x)
1/x will be greater than x. If you arrange them in order you see that x will be in the middle and hence the median.

Calista.
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by preciousrain7 » Thu Dec 27, 2007 3:28 pm
StarDust845 wrote:0<x<1

For given x, sqrt(x) is greater than x.
square(x) is less than x.
cube(x) will be less than square(x)
1/x will be greater than x. If you arrange them in order you see that x will be in the middle and hence the median.

Calista.
Thanks! All this time I was thinking sqrt (x) is less than x.
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