BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

GMAT prep intercept problem

Expert replies
Source: — Problem Solving |

by sanju09 » Fri Jan 08, 2010 3:08 am
The two lines l and k are intersecting in the first quadrant. A line with +ve or -ve x or y-intercept can have its slope of either sign and two non parallel lines can intersect each other in any quadrant.

(1) The product of two x-intercepts is positive, that means both the x-intercepts are either +ve or -ve. But the slopes do not depend on x-intercepts only; as slope of a line = - (y-intercept)/(x-intercept). Insufficient

(2) The product of two y-intercepts is negative, that means both the y-intercepts are of opposite sign. But the slopes do not depend on y-intercepts only; as slope of a line = - (y-intercept)/(x-intercept). Insufficient

Amalgamating (1) & (2) gives that with same signs of x-intercepts, different signs of y-intercepts would definitely generate two slopes of different signs, and hence their product will definitely be negative. Sufficient


IMO C
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Join the discussion