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GMAT Prep Geometry Question

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by havok » Sat Apr 30, 2011 8:48 pm
ri2007 wrote:Diameter is 18 so circumference of semi circle = 18 pi /2 = 9 pi

PQ ll OR so angle R = angle P = 35

so arc OP = arc QR = 35 * 2 = 70

so arc PQ = 180 - ( arc OP + arc QR) = 40 deg

Since 180 deg corresponds to 9 pi

40 corresponds to 2 pi ( cross multiplication)
'


Wow I did NOT see that solution, thanks!
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