BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

GMAT Prep - Functions Question - Weird

Expert replies
by tutonaranjo » Thu Aug 30, 2007 11:20 am
For every positive even integer n, the function h(n) is defined to be the product of all the even integers from 2 to n, inclusive. if p is the smallest prime factor of h(100) + 1, then p is:
a) between 2 and 10
b) between 10 and 20
c) between 20 and 30
d) between 30 and 40
e) greater than 40

The answer is E.
I can't even begin to tell you how little I understand this question. Really appreciatte a detailed explanation from someone who gets this.
Join the discussion
Source: — Problem Solving |

by keepsmilinyaar » Sat Sep 01, 2007 12:00 pm
I couldnt get the answer so searched online for it.

Credit goes to dumbJOE if dats his real name:

Explanation:
h(n) = 2 * 2x2 * 2x3 * 2x4 * 2x5 * 2x6 * 2x7 * ....................................
so if n is an even number, all numbers from 1 to n/2 are factors of h(n). This implies that for n=100. 1 to 50 are factors, the last prime number is 47 here. hence if we add 1 to h(n) we cannot get a factor among 1 to 50 for sure, because since h(n) was a multiple of each one of them individually, you need to add atleast the factor itself to get yet another multiple. Since the smallest prime number is 2, this requisite minimum accretion comes to 2.
Join the discussion