hi guys,
can the solution to this qs be as follows?
let the 5 diff numbers be n, n+1, n+2, n+3, n+4. therefore the qs asked, (n+3) + (n+4)/2 > 70?
or 2n+7>140 --> n> 66.5?
st1: n+2 = 70 or n = 68 --> SUFF
st2: mean 5n+10/5=70 --> 5n=340 --> n=68 --> SUFF
Is it wrong to use consecutive integers as an example to solve the above?
Response appreciated!
can the solution to this qs be as follows?
let the 5 diff numbers be n, n+1, n+2, n+3, n+4. therefore the qs asked, (n+3) + (n+4)/2 > 70?
or 2n+7>140 --> n> 66.5?
st1: n+2 = 70 or n = 68 --> SUFF
st2: mean 5n+10/5=70 --> 5n=340 --> n=68 --> SUFF
Is it wrong to use consecutive integers as an example to solve the above?
Response appreciated!
