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by aanchalsinha » Sat Sep 03, 2011 12:16 am
hi guys,

can the solution to this qs be as follows?

let the 5 diff numbers be n, n+1, n+2, n+3, n+4. therefore the qs asked, (n+3) + (n+4)/2 > 70?
or 2n+7>140 --> n> 66.5?

st1: n+2 = 70 or n = 68 --> SUFF
st2: mean 5n+10/5=70 --> 5n=340 --> n=68 --> SUFF

Is it wrong to use consecutive integers as an example to solve the above?

Response appreciated!

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by prateek_guy2004 » Sat Sep 03, 2011 1:35 pm
A certain list consists of five different integers. Is the average of the two greatest integers in the list greater than 70?

a. The median of the integers in the list is 70

for example 50 +60+ 70+(80+90)

if median is 70 then the two greatest digit will be grater that 70...

Hence can be answered.. sufficient

b. The average of the integers in the list is 70.

now if average is 70 which is 70 * 5= 350

So we can answer that the greatest two digits are greater than 70 or no.

sufficient

Hence D
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