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GMAT Prep / Combinatorics

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Source: — Problem Solving |
Senior | Next Rank: 100 Posts
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by muzali » Tue Dec 02, 2008 5:22 pm
Atleast one French member = (1F out of total 3)+(2F out of total 3)+(3F out of total 3)

=(4C1*6C2) + (4C2*6C1) + (4C3)
=4*15 + 6*6 + 4
=60+36+4
=100
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Master | Next Rank: 500 Posts
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by jimmiejaz » Wed Dec 03, 2008 7:21 am
You can also solve this question as....
We have to find no of ways containing atleast one french.
We can find no of ways in which no french member is selected and subtract it from total.
10C3 - 6C3
= 100
What if i have not yet beat the beast, I know i will beat it!!!!!!!!
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Senior | Next Rank: 100 Posts
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by Carloblacksun » Wed Dec 03, 2008 7:55 am
I had the same approach as Jimmy!!
Good one!
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