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by dferm » Tue Mar 25, 2008 8:01 am
Alice's take-home pay last year was the same each month, and she saved the same fraction of her take-home pay each month. The total amount of money that she had saved at the end of the year was 3 times the amount of that portion of her monthly take-home pay that she did NOT save. If all the money that she saved last year was from her take-home pay, what fraction of her take-home pay did she save each month?

A. 1/2
B. 1/3
C. 1/4
D. 1/5
E. 1/6

PLEASE HELP..
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by xilef » Tue Mar 25, 2008 11:08 am
S - total amount of money that she had saved at the end of the year
T - monthly take-home pay

S/12 - saved amount each month since take-home pay last year was the same each month, and she saved the same fraction of her take-home pay each month.


S = 3(T-S/12)
S = 12T/5

S/12 = 12T/60=T/5

Answer 1/5.

OR


S - total amount of money that she had saved each month
T - monthly take-home pay

3(T-S)=12S
S=T/5
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by aj5105 » Thu Oct 02, 2008 7:51 am
Let T be the take home each month.

Let's take T/x part was saved each month.

in a yr's time =saved money = 12T/x = 3(T - T/x)
Solving the equation we get x = 5.

T/x = T/5 Hence 1/5.
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