dferm wrote:Please Help.... A little confused....

Itz D

Take an example of A.BCD here .

C in the decimal A.BCD is the hundredth digit.

Statement 1.

when u multiply it by 10 , the 100th digit will move to the left and becomes the tenth digit B.CD

So, if in 10d C is the hundredth digit, then in the decimal, C is the tenth digit.

hence sufficient

Statement 2.

Its the same as first , except it says the decimal is divided by 10 .. so C will move to the right and will become 1000th digit.

thus A.BCD will A.0BCD.

thus sufficient

hope this helps

Not quite getting this explanation....

dferm wrote:Not quite getting this explanation....

okai ..let me try using numbers

take an example

Assume D= 1.2736

2 is the tenth digit , 7 is the hundredths digit, 3 is the thousandths digit and so on

statement 1 says .

if D is multiplied by 10, tenths digit is 7

1.2736*10 = 12.736 here 7 is in tenth digit.

hence sufficient

statement 2.

D= 1.2736

when D is divided by 10 , thousandth digit will be 7

1.2736/10 = 0.12736 7 is in thousandth digit.

hence sufficient.

hope that helps

Do let me know if this helps

10d = tenth digit is 7 is the same as saying
d's hundreth dgit is 7
Take d = 1.07
10d = 10.7


Similarly for II.

But how does this relate to the question of the hundredth digit being greater than 5.... I am not getting your explanations.....

NEED BETTER STRATEGY......

ANYBODY....

Thanks...

GOT IT.... THANKS>..

Okay .. Can someone say is it greater than 5 or not ?

Because in the example above 1.2735 less than 5, however we could have another number where the hundredths digit greater than 5 without rounding it up. for example 1.2763 and its still satisfied statement one alone and statement two alone. Can anyone explain ??

Hello abdulla,

you seem to have misinterpreted the question and the answers given here....

the question clearly gives out the number which is asked to be defined as odd or even...

consider d = 10.8x3

here the hundredths digit is 'x'...

now, consider multiplying d by 10, u get,

108.x3

the hundredths digit HAS BECOME the tenths digit....which is given to be 7

hence, condition 1 alone is enough


Now condition 2

divide d by 10

u get 1.08x3

the hundredths position has now become the thousandths position.

which is again given to be 7....hence, we know our x = 7....
Hence, statement 2 alone is also enough..

Hence, option D

Thanks buddy... it's clear now