BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

GMAT Prep 1 PS 31

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
Legendary Member
Posts: 645
Joined: Wed Sep 05, 2007 4:37 amFollowed by: 5 members
Location: India
Thanked: 34 times

by camitava » Sun Dec 30, 2007 9:21 pm
starxx68,
Total population = 132,000 Cities = 11
So if equally distributed, each city would have = 12,000 population.
But now if 10% of population can vary in each city.
So minimum range of population that a city can have = (90/100 * 12000) = 10,800 and maximum = (110/100 * 12000) = 13200. So the minimum population that a city can have = 11000. IMO D.
Correct me If I am wrong


Regards,

Amitava
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 26
Joined: Sun Dec 30, 2007 10:30 pm
Thanked: 1 times

by specialk1975 » Sun Dec 30, 2007 11:05 pm
You can back solve this one:

Take the 11,000

1) 132000 - 11000 = 121,000 "remaining population"
2) 121,000/ 10 (the remaining cities) = 12,100 (per city)
3) (12,100-11,000)/ 11,000 = 10%

*If you take the 10800 choice, you get 12% which is to high.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Senior | Next Rank: 100 Posts
Posts: 77
Joined: Mon Jul 09, 2007 6:54 pm
Location: US of A

by Auzbee » Mon Dec 31, 2007 7:12 pm
So minimum range of population that a city can have = (90/100 * 12000) = 10,800 and maximum = (110/100 * 12000) = 13200. So the minimum population that a city can have = 11000. IMO D.
Amitava,
In your explanation why did you choose 11000 and not 10900?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 645
Joined: Wed Sep 05, 2007 4:37 amFollowed by: 5 members
Location: India
Thanked: 34 times

by camitava » Mon Dec 31, 2007 11:36 pm
Hey Auzbee! U r right man. It should be 10900 but not 11000. A miss from y side. However thanks Auzbee for pointing out my mistake.
Correct me If I am wrong


Regards,

Amitava
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1