BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Gmat Prep_02

Expert replies
by gdk800 » Sun Nov 28, 2010 9:57 pm
1) If n denotes a number to the left of 0 on the number line such that square of n is less than 1/100. Then reciprocal of n must be
a. Less than -10.
b. Between -1 and -1/10.
c. Between -1/10 and 0.
d. Between 0 and 1/10.
e. Greater than 10.

OA is A

2) A car averages 25 miles/gallon when driven in city and 40 miles/gallon when driven on highway. According to these rates, which of following is closest to the number of miles per gallon that the car averages when it is driven 10 miles in the city and then 50 miles on the highway?
a. 28
b. 30
c. 33
d. 36
e. 38

OA is D

3) Attached is an image. On the number line, its visible that according to Option B (z>y) is true but its not the OA.

OA is E

Image
Join the discussion
Source: — Problem Solving |

by Rahul@gurome » Sun Nov 28, 2010 10:07 pm
Question Number 1:
gdk800 wrote:1) If n denotes a number to the left of 0 on the number line such that square of n is less than 1/100. Then reciprocal of n must be
a. Less than -10.
b. Between -1 and -1/10.
c. Between -1/10 and 0.
d. Between 0 and 1/10.
e. Greater than 10.

OA is A
As, n² < 1/100
=> -1/10 < n < 1/10
=> n > -1/10 ........... As n < 0
=> 1/n < -10 ........... Change of inequality sign as n < 0

The correct answer is A.
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
Join the discussion

by Rahul@gurome » Sun Nov 28, 2010 10:15 pm
Question Number 2:
gdk800 wrote:2) A car averages 25 miles/gallon when driven in city and 40 miles/gallon when driven on highway. According to these rates, which of following is closest to the number of miles per gallon that the car averages when it is driven 10 miles in the city and then 50 miles on the highway?
a. 28
b. 30
c. 33
d. 36
e. 38

OA is D
Miles driven in city = 10 => Fuel consumed = 10/25 gallons
Miles driven on highway = 50 => Fuel consumed = 50/40 gallons

Total fuel consumed = (10/25 + 50/40) gallons = (80 + 250)/200 gallons = 33/20 gallons
Total distance traveled = (10 + 50) miles = 60 miles

Average miles per gallons = 60/(33/20) = (60*20)/33 = (20*20)/11 ≈ 36

The correct answer is D.
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
Join the discussion

by Rahul@gurome » Sun Nov 28, 2010 10:29 pm
gdk800 wrote:3) Attached is an image. On the number line, its visible that according to Option B (z>y) is true but its not the OA.

OA is E
No, it's not! :)
Option B says xz > xy!
Now as x < 0, canceling x on both sides will reverse the inequality sign! (Think about it!) Thus, z < y, which is not true.

To solve the problem analyze the options one by one.
  • (1) x + y > y => As x and y both negative (x + y) certainly less than both x and y. INCORRECT
    (2) xz > xy => Explained earlier! (Another explanation : x and y negative but z positive => xz always negative and xy always positive => xy > xz) INCORRECT
    (3) tz < z => As z is positive this implies t < 1. INCORRECT
    (4) m^u < 0 => m = -1, u = 2 => m^u = 1. INCORRECT
    (5) t^m > 0 => t is positive and m = -1 => t^m = t^(-1) = 1/t > 0. CORRECT
The correct answer is E.
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
Join the discussion

by gdk800 » Sun Nov 28, 2010 11:42 pm
Thanks Rahul, yes i realized about the 3rd question as soon as you wrote x is less than 0.
But could you please elaborate on the 1st question a bit more.

As n > -1/10
=>10 > -1/n
Multiplying both sides by -1 and thus the inequality reverses sign
=>-10 < 1/n

Thus 1/n should be greater and not less than -10.....

Plz explain!!!
Join the discussion

by Rahul@gurome » Sun Nov 28, 2010 11:58 pm
gdk800 wrote:Thanks Rahul, yes i realized about the 3rd question as soon as you wrote x is less than 0.
But could you please elaborate on the 1st question a bit more.

As n > -1/10
=>10 > -1/n [As n is negative, cross multiplication will also revert the inequality sign! Thus it will be 10 < -1/n]
Multiplying both sides by -1 and thus the inequality reverses sign
=>-10 < 1/n

Thus 1/n should be greater and not less than -10.....

Plz explain!!!
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
Join the discussion