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GMAT PowerPrep Question 3 - Practice Exam

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Junior | Next Rank: 30 Posts
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by weipei » Fri May 04, 2007 1:32 am
Can someone explain how to get this answer? Thank you!!!

For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative. What is the variation in sign for the sequence 1, -3, 2, 5, -4, -6?

o One
o Two
o Three
o Four
o Five
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by mschling52 » Fri May 04, 2007 4:32 am
I think it's C - three, since

1*-3 = negative
-3*2 = negative
5*-4 = negative
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by Cybermusings » Fri May 04, 2007 11:46 am
For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative. What is the variation in sign for the sequence 1, -3, 2, 5, -4, -6?

A)One
B)Two
C)Three
D)Four
E)Five

Three
(1,-3), (-3,2), (5,-4)
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by weipei » Fri May 04, 2007 7:30 pm
Thanks you guys!
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