BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

GMAC paper based tests

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
User avatar
Legendary Member
Posts: 986
Joined: Wed Dec 20, 2006 11:07 amFollowed by: 1 member
Location: India
Thanked: 51 times

Re: GMAC paper based tests

by gabriel » Sat May 12, 2007 7:34 am
Cybermusings wrote:OA coming in after explanations
… we need to find x to find the area … point to remember … the perpendicular to the unequal side from the opposite angle will divide the unequal into 2 equal parts ..

so accordingly we have from the Pythagoras theorem … (2x-2)^2=x^2+((3x-2)/2)^2 … solving this we get the quadratic eqn .. 3x^2-20x+12 = 0 .. solving the quadratic eqn we get 2 possible values for x 2/3 and 6 .. but x cant be 2/3 coz then the base wuld be equal to 0 … so taking the value of x as 6 we get the base is equal to 16 and the perpendicular equal to 6 .. so the area is equal to 16*6/2 = 48 .. so the answer is C …
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 33
Joined: Sat Apr 14, 2007 8:29 am

by ns88 » Sat May 12, 2007 9:03 am
since isosceles triangle

2x-2=3x-8

x=6


area =(3x-2) (x)1/2 =48

ans=c
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 55
Joined: Sun Apr 29, 2007 6:25 am
Location: MA
Thanked: 1 times

by bww » Sat May 12, 2007 11:07 am
A=(1/2)(3x-2)(x)
=(3x^2-2x)/2

2x-2=3x-8
x=6

(3(3)^2-2(6))/2
=48 or C
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1