GMAC paper based test

I will answer 13th question - it was interesting to me.

line between points
(0;30) and (50;0)
how many interegs?

to test each point looks crazy

foemula for the line between points (0;30) and (50;0) is
y= -3/5*x + 30

How many integers for x and y?
y(should be integer)= -3/5*x (should be integer) + 30 (integer)
so we should test
y= -3/5*x
if 3/5*x should be an integer, than x should be any multiply of 5
and since we know that 0<x<50
we are letf only with 0, 5, 10, .... 50 - total 11 integers.

So, I think the answer is 11

D

OA?




14.
C
10^100 has 101 digits

I will give the first question a whirl:

148 documents with an average of 10 pages per document = 1480 pages

15 seconds a page = 22, 200 seconds

There are 3600 seconds in an hours, Thus:

22200/3600 = 222 / 36 (I reduced both numbers and elimnated the zeros)

222/36 = Approximately 6 Answer D.

The second question is interesting. I think it it trying to sound a little more complicated than it is. This is how I went about it. Ultimately, you are trying to get:

3 + 4/sqrt (5-x) to equal to 6 OR basically

4/sqrt(5-x) to equal to 3.

So the question is - what goes into 4 and equals 3? Approximately 1.3. So we are trying to get the denominator sqrt(5-x) to equal to about 1.3.
We know from our practice that sqrt(2) is approximately 1.4, so we need (5-x) to equal a little less than 2.

After looking at the answer choices - IMO 3.2 was the closest. Choice E.

i vote for E for q 14. think about it this way -

10^2 = 100
100/100 = 1

so you need 1 more number in the denom to make this a decimal.

hello all,

thanks for your replies and explanations...the OAs are:
4-D
16-E
13-D
14-C