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age together. What is it?

Problem Solving — algebra and arithmetic (GMAT Focus Edition)
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age together. What is it?

by sanju09 » Mon Nov 14, 2011 2:56 am
George was a 76 year old man who lived a mansion that was 4 stories tall. His neighbor's house is 2 stories tall. George's brother is 59, and owns a shack that has 1 story, and it's kitchen is 20 square feet. George is a pharmacist, and sells about 179 prescriptions a day. His brother is a doctor and deals with about 67 patients a day.Add George and his brother's age together. What is it?
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by neelgandham » Mon Nov 14, 2011 3:03 am
= 76+59 = 135 (If George is a 76 year old man who lived a mansion that was 4 stories tall):lol:
Last edited by neelgandham on Mon Nov 14, 2011 3:40 am, edited 1 time in total.
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by shankar.ashwin » Mon Nov 14, 2011 3:09 am
Sanju? why such weird questions? :)
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by sanju09 » Mon Nov 14, 2011 3:48 am
shankar.ashwin wrote:Sanju? why such weird questions? :)
:-) ok answer this

600 people voted on a resolution, but after some discussion, the opponents were increased by 150%. The motion was then rejected by a majority two times as great as that by which it was formerly passed. How any voted for and how many voted against the initial resolution?
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by shankar.ashwin » Mon Nov 14, 2011 3:55 am
Case 1:

Total = 600 + Opponents.

Case 2:

Total = 600 + 1.5 Opponents.

Given, 1.5 Opponents = 2 (600)

Therefore, Opponents = 800 and Voters = 600.


sanju09 wrote:
600 people voted on a resolution, but after some discussion, the opponents were increased by 150%. The motion was then rejected by a majority two times as great as that by which it was formerly passed. How any voted for and how many voted against the initial resolution?
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by neelgandham » Mon Nov 14, 2011 4:22 am
sanju09 wrote: 600 people voted on a resolution, but after some discussion, the opponents were increased by 150%. The motion was then rejected by a majority two times as great as that by which it was formerly passed How any voted for and how many voted against the initial resolution?
let
voters who voted 'for' the resolution = x and
voters who voted 'against' the resolution = y

x+y = 600 and
The margin or majority = x-y (As the resolution was passed the first time)

voters who voted 'against' the resolution after the discussion = y + ((3/2)*y)
voters who voted 'for' the resolution after the discussion = x - ((3/2)*y)
The resolution was rejected. So, the majority = y + ((3/2)*y) - [x - ((3/2)*y)] = 4y-x

4y-x = 2(x-y)
4y-x=2x-2y
6y=3x
x =2y

x+y =600
x=2y
=> 3y=600 , y = 200 and x = 400

voters who voted 'for' the resolution = 400 and
voters who voted 'against' the resolution = 200
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