Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 563 reviewsTarget Test Prep

Geometry

Expert replies
Post new topic Post Reply
Subscribe topic
Previous Topic Next Topic
Senior | Next Rank: 100 Posts
Posts: 49
Joined: Thu Aug 26, 2010 11:08 pm
Thanked: 2 times
by narik11 » Thu Sep 30, 2010 7:54 am
A closed cylindrical tank contains 36n cubic feet of water and is filled to half its capacity. When the tank is placed upright on its circular base on level ground,the height of the water in the tank is 4 feet. When the tank is placed on its side on level ground, what is the height, in feet, of the surface of the water above the ground?
Top
Join the discussion
Source: — Problem Solving |
User avatar
Legendary Member
Posts: 1893
Joined: Sun May 30, 2010 11:48 pmFollowed by: 7 members
Thanked: 215 times

by kvcpk » Thu Sep 30, 2010 8:14 am
narik11 wrote:A closed cylindrical tank contains 36n cubic feet of water and is filled to half its capacity. When the tank is placed upright on its circular base on level ground,the height of the water in the tank is 4 feet. When the tank is placed on its side on level ground, what is the height, in feet, of the surface of the water above the ground?
Volume of cylinder = pi*r^2*h = 72pi
Hence r^2*h = 72
Height of the tank is 4*2 = 8 feet
Hence r^2 = 72/8 = 9
So r=3

Water should be of the height of radius when placed on ground with its surface. Hence the height should be 3.

Whats OA?
"Once you start working on something,
don't be afraid of failure and don't abandon it.
People who work sincerely are the happiest."
Chanakya quotes (Indian politician, strategist and writer, 350 BC-275BC)
Top
Join the discussion
Master | Next Rank: 500 Posts
Posts: 270
Joined: Wed Apr 07, 2010 9:00 amFollowed by: 2 members
Thanked: 24 times

by neerajkumar1_1 » Thu Sep 30, 2010 8:19 am
narik11 wrote:A closed cylindrical tank contains 36n cubic feet of water and is filled to half its capacity. When the tank is placed upright on its circular base on level ground,the height of the water in the tank is 4 feet. When the tank is placed on its side on level ground, what is the height, in feet, of the surface of the water above the ground?
Under the assumption that the height of the water when the cylinder is placed laterally will be the radius of its base
we need to find 'r'
at height of 4 feet... the volume is 36 cubic feet

pie * r^2 * 4 = 36 * pie

r = 3
Top
Join the discussion
Senior | Next Rank: 100 Posts
Posts: 49
Joined: Thu Aug 26, 2010 11:08 pm
Thanked: 2 times

by narik11 » Thu Sep 30, 2010 8:29 am
kvcpk wrote:
narik11 wrote:A closed cylindrical tank contains 36n cubic feet of water and is filled to half its capacity. When the tank is placed upright on its circular base on level ground,the height of the water in the tank is 4 feet. When the tank is placed on its side on level ground, what is the height, in feet, of the surface of the water above the ground?
Volume of cylinder = pi*r^2*h = 72pi
Hence r^2*h = 72
Height of the tank is 4*2 = 8 feet
Hence r^2 = 72/8 = 9
So r=3

Water should be of the height of radius when placed on ground with its surface. Hence the height should be 3.

Whats OA?
its 3
Top
Join the discussion