Geometry

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harsh.champ: Legendary Member; Posts: 1132; Joined: Mon Jul 20, 2009 3:38 amFollowed by: 6 members; Location: India; Thanked: 64 times; GMAT Score:760

by harsh.champ » Fri Feb 19, 2010 8:03 am

A and B are equidistant from the line l. How many circles can be drawn with their centres on line l and that pass through both A and B?

A. 1
B. 2
C. 3
D. 4
E. >10

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Source: Beat The GMAT — Problem Solving | Fri Feb 19, 2010 8:03 am

Mom4MBA: Senior | Next Rank: 100 Posts; Posts: 90; Joined: Fri Jan 22, 2010 1:10 pmFollowed by: 4 members; Location: New Jersey; Thanked: 13 times; GMAT Score:640

by Mom4MBA » Fri Feb 19, 2010 9:02 am

answer >10, it can be any number of circles because the center of circle can be anywhere on the line L, center in not the intersection of line L and line AB had it been the case the solution would have been 1

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shashank.ism: Legendary Member; Posts: 1022; Joined: Mon Jul 20, 2009 11:49 pmFollowed by: 2 members; Location: Gandhinagar; Thanked: 41 times

by shashank.ism » Fri Feb 19, 2010 10:10 am

harsh.champ wrote:A and B are equidistant from the line l. How many circles can be drawn with their centres on line l and that pass through both A and B?

A. 1
B. 2
C. 3
D. 4
E. >10

since centre lies on line l i.e. l is the locus of radius .so taking it as diameter of the various circle you will find you can draw infinite no. of circles with centre on line l and chord as AB. though u will get only one circle ehre this chord Ab will be diamete.

So ans E

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