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by parveen110 » Wed May 28, 2014 3:09 am
In the figure, ABE, DCE, BCF and ADF are straight lines. Angle E=50 deg., Angle F=56 deg. Find Angle A.
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by theCodeToGMAT » Wed May 28, 2014 8:00 am
Is there is some missing information?

What is the source? Can you post complete Q along with answer choices.
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by Brent@GMATPrepNow » Wed May 28, 2014 8:19 am
theCodeToGMAT wrote:Is there is some missing information?

What is the source? Can you post complete Q along with answer choices.
You're almost there, theCodeToGMAT.

Unfortunately, this question requires us to apply a circle property that is not tested on the GMAT.
Quadrilateral ABCD is a cyclic quadrilateral, and the OPPOSITE angles in a cyclic quadrilateral always add to 180º

So, ∠B + ∠D = 180
So, (50 + x) + (56 + x) = 180
Simplify: 106 + 2x = 180
Solve to get: x = 37

Also, if ∠C = 180-x (as you have noted), then ∠A = x [so that ∠A + ∠C = 180]
So, x = [spoiler]37º[/spoiler]

Cheers,
Brent
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by theCodeToGMAT » Wed May 28, 2014 9:45 am
Thanks Brent!...
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