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by shankar.ashwin » Mon Jan 30, 2012 4:40 am
Though not given, we could infer from the figure the 4 triangles are 6-8-10 right triangles. Perimeter would be 6+8+10 = 24
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by GMATGuruNY » Mon Jan 30, 2012 5:14 am
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Common sense tells us that the four triangles are congruent right triangles.

Inner square:
Since p=8, s=2 and A = 2² = 4.

Each triangle:
Since the area of the inner square = 4, and the area of the outer square = 100, the area of each triangle = (100-4)/4 = 24.

ALWAYS LOOK FOR SPECIAL TRIANGLES.

Since the hypotenuse of each triangle is 10, it is likely that each triangle is a 6-8-10 triangle.
In a 6-8-10 triangle, A = (1/2)bh = (1/2)(6)(8) = 24. This works.
Thus, p = 6+8+10 = 24.

The correct answer is E.
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by marakocho » Mon Jan 30, 2012 8:33 am
AB=100/10=10
AB^2=AC^2+BC^2
10^2=8^2+6^2
hence, P=10+8+6=24
Ans E
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