BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Geometry Rule Question

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Senior | Next Rank: 100 Posts
Posts: 60
Joined: Sun Jan 24, 2010 2:29 pm
Thanked: 3 times
by jeremy8 » Sat Jul 03, 2010 5:04 pm
Given the relationship which states that "Angles correspond to their opposite sides", is it correct to assume there is a proportional relationship between the ratios of angle to side-lenght and vice versa within a triangle?

for example, in triangle ABC, if we are given the lenght of side AB as 5 units and the angle opposite to side AB as 35 degrees, would it be correct to assume that within this triangle, if the angle opposite side BC is 70 degrees, then BC would equal 10 units?

Basically, is it possible to just establish a proportion such as 35/5 = 70/x with x being the lenght of side BC? And the opposite as well of course, establishing angle size based on side-lenght proportion.

Thank you
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
User avatar
Legendary Member
Posts: 1893
Joined: Sun May 30, 2010 11:48 pmFollowed by: 7 members
Thanked: 215 times

by kvcpk » Sat Jul 03, 2010 9:16 pm
Unfortunatley, the answer is NO. I believe the sides will be in proportion, but not in equal proportion..
You can say that the side opposite to the largest angle will be the longest side and the side opposite to the shortest angle will be shortest side.

Let me give a small example:

assume a right angled triangle with 30-60-90
let the side opposite 30 be x.
then , we know that the ratio of sides in 30-60-90 triangle is 1:root(3):2

Hence, the side opposite to 90 is 2x and not the side opposite to 60.

So, there exists no such proportion for all triangles.. Geometry does not make our lives so easy :)

A triangle's complete informaton can be found if any of these three are given:
1. three side lengths
2. two sides and the angle between them
3. two angles and the side between them.

If you can find any of the three above, then you can find the complete triangle measurements.

Hope this helps!!

Praveen
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 60
Joined: Sun Jan 24, 2010 2:29 pm
Thanked: 3 times

by jeremy8 » Sat Jul 03, 2010 9:25 pm
Praveen,

Thanks for your help. I guess it was nothing more than a nice idea...
Time to stop dreaming about reinventing geometry and back to my books :lol:
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 1893
Joined: Sun May 30, 2010 11:48 pmFollowed by: 7 members
Thanked: 215 times

by kvcpk » Sat Jul 03, 2010 9:52 pm
jeremy8 wrote:Praveen,

Thanks for your help. I guess it was nothing more than a nice idea...
Time to stop dreaming about reinventing geometry and back to my books :lol:
Kewl :D
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members
Location: New York, NY
Thanked: 13060 times
GMAT Score:790

by GMATGuruNY » Mon Jul 05, 2010 9:07 am
All triangles exhibit the following proportionality:

In triangle ABC:

length AB/sin(angle opposite AB) = length BC/sin(angle opposite BC) = length AC/sin(angle opposite AC).

This rule of proportionality is not tested on the GMAT, so you shouldn't worry about it. The GMAT does not ask questions for which a knowledge of trigonometry is needed.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 60
Joined: Sun Jan 24, 2010 2:29 pm
Thanked: 3 times

by jeremy8 » Mon Jul 05, 2010 9:11 am
GMATGuruNY wrote:All triangles exhibit the following proportionality:

In triangle ABC:

length AB/sin(angle opposite AB) = length BC/sin(angle opposite BC) = length AC/sin(angle opposite AC).

This rule of proportionality is not tested on the GMAT, so you shouldn't worry about it. The GMAT does not ask questions for which a knowledge of trigonometry is needed.
Thanks. Even though it is not tested on the GMAT, I'm really interested in that relationship and I'll definitely look into it more (after I take the test...)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1