BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Geometry:Right angle property

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 217
Joined: Sun Jan 10, 2010 1:39 pmFollowed by: 1 member
Thanked: 7 times
by zaarathelab » Mon Dec 12, 2011 7:44 am
Pls see attachment.
If Triangle BAD is a right angle, what is the length of side BD?

1)AC is perpendicular to BD
2)BC = CD


Experts, need your comments
Attachments
geometry.doc
(31 KiB) Downloaded 108 times
Success = Max(Hardwork) + Min(Luck)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Data Sufficiency |
User avatar
Legendary Member
Posts: 588
Joined: Sun Oct 16, 2011 9:42 amFollowed by: 9 members
Location: New Delhi, India
Thanked: 130 times
GMAT Score:720

by rijul007 » Mon Dec 12, 2011 8:17 am
Statement 1
AC perpendicular to BD
tells us nothing

Its insufficient


Statement 2
BC = CD

We have no clue what point C is..
Insufficient


Combining two statements ...
AC perpendicual to BD and BC= CD

triangle ACB and triangle ACD will be congruent
AB = AC = 5
BC = 5*rt(2)


Option C
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 3835
Joined: Fri Apr 02, 2010 10:00 pmFollowed by: 523 members
Location: Milpitas, CA
Thanked: 1854 times
GMAT Score:770

by Anurag@Gurome » Mon Dec 12, 2011 9:48 pm
zaarathelab wrote:Pls see attachment.
If Triangle BAD is a right angle, what is the length of side BD?

1)AC is perpendicular to BD
2)BC = CD

Experts, need your comments
(1) AC is perpendicular to BD does not help us to find the length of BD; NOT sufficient.

(2) BC = CD
Triangles ACB and ACD are congruent to each other, as BC = CD, AC = AC(common). Since the two triangles are congruent, so AB = AD = 5. BAD is right angled at A, so by Pythagoras Theorem, we can find BD; SUFFICIENT.

The correct answer is B.
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 217
Joined: Sun Jan 10, 2010 1:39 pmFollowed by: 1 member
Thanked: 7 times

by zaarathelab » Tue Dec 13, 2011 12:43 am
OA is C

Anurag, can you pls illustrate the relationships in this special type of right angled triangle with respect to:
1. AC is perpendicular to BD
2. AC is a median
3. AC is a perpendicular bisector of BD

My take

1. AC is perpendicular to BD MEANS AC^2 = BC*CD (All triangles are similar)
2. AC is a median MEANS BC=CD and all triangles are similar (BA=BC) ABD is an isoceles triangle (AD=AB)
3. AC is the perpendicular bisector of BD MEANS BC=CD and all triangles are similar (BA=BC) ABD is an isoceles triangle (AD=AB)

I often get confused with this type of triangle

Thanks
Success = Max(Hardwork) + Min(Luck)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1