amontobin wrote:What is the area of rectangular garden R?
(1) The length of the garden is twice the width.
(2) The perimeter is 84 yards.
Statement 1: L = 2W
Case 1: L=2 and W=1, with the result that A = LW = 2*1 = 2.
Case 2: L=4 and W=2, with the result that A = LW = 4*2 = 8.
Since the area can be different values, INSUFFICIENT.
Statement 2: 2L + 2W = 84, implying that L+W = 42.
Case 1: L=41 and W=1, with the result that A = LW = 41*1 = 41.
Case 2: L=40 and W=2, with the result that A = LW = 40*2 = 80.
Since the area can be different values, INSUFFICIENT.
Statements combined:
Since we have two variables (L and W) and two distinct linear equations with these variables (L=2W and L+W = 42), we can solve for the two variables.
Since we can solve for L and W, the area of the rectangle can be determined.
SUFFICIENT.
The correct answer is
C.
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